Answer:
A)11
Step-by-step explanation:
These are matrices one dimensional with one column and 3 rows each.
-The product of the matrices is obtained by multiplying the correspond values and summing up;
![pq=\left[\begin{array}{ccc}3\\2\\-1\end{array}\right] \times\left[\begin{array}{ccc}5\\-1\\2\end{array}\right] \\\\\\\\=(3\times 5)+(2\times -1)+(-1\times 2)\\\\=15+-2+-2\\\\=11](https://tex.z-dn.net/?f=pq%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C-1%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C-1%5C%5C2%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5C%5C%3D%283%5Ctimes%205%29%2B%282%5Ctimes%20-1%29%2B%28-1%5Ctimes%202%29%5C%5C%5C%5C%3D15%2B-2%2B-2%5C%5C%5C%5C%3D11)
Hence, the product of p and q is 11
Answer: cool!
Step-by-step explanation: ;)
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
Answer:
x>1
Step-by-step explanation:
Answer:
Step-by-step explanation:
These two expressions are definitely not equal.
4 7/9 is a repeating decimal: 4.77777 ... (use your calculator)
whereqs 4.7 is NOT a repeating decimal.