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2 years ago

14

At a camp, kids can choose swimming, art, or music. 40 kids choose swimming, 16 choose art, and 24 choose music. What is the rat

io of kids who choose music to kids who choose swimming?

2 answers:

Svetradugi [14.3K]2 years ago

8 0

Answer:

13 : 20

Step-by-step explanation:

Given that:

40 kids choose swimming
24 choose music
16 choose art

So the ratio of kids who choose music to kids who choose swimming:

Number of kids choose music : Number of kids choose swimming

26 : 40

= 13 : 20

Hope it will find you well

Dovator [93]2 years ago

6 0

Answer:

3:5

Step-by-step explanation:

The question here says that at a camp, kids can choose swimming, art, or music. 40 kids choose swimming, 16 choose art, and 24 choose music. What is the ratio of kids who choose music to kids who choose swimming?

----- Number of kids that like swimming is 40,the number of kids that like arts is 16 and the number of kids that prefer music is 24.

If you take a proper look at all these different figures,you'd realize that they are all divisible by 8

Swimming = 40/8 = 5

Arts = 16/8 = 2

And music = 24/8 = 3

The ratio of kids that choose music to swimming is 3:5

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Pie

Answer:

A straight line is equivalent to 180 degrees with that in mind,

(2.4x)+(9.6x)=180
2.4x+9.6x=180
12x=180
12x/12=180/12
x=15

Now to find the measurement of the larger angle,

9.6*15=144
Just in case you need it
180-144=36
Which is your smaller measurement.

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3 years ago

Can anyone plzzzz help me with this question of linear equation in two varaiable plzzzzzz... Its very important... Plz solve it

kotegsom [21]

That's not a linear system, but you have an awesome school system for giving you this problem.

$\dfrac 5 y - \dfrac 2 x = \dfrac{13}6$

Multiply by 6xy to clear the fractions.

$30x - 12y = 13 xy$

That's a second degree equation, also known as a conic. That one happens to be a hyperbola.

$30x = y(13 x +12)$

$y = \dfrac{30x}{13 x + 12}$

Let's clear the fractions from the second equation, multiplying out common denominator xy:

$\dfrac {36} x - \dfrac {24} y = 1$

$36y - 24 x = xy$

We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.

Substituting,

$36 \left( \dfrac{30x}{13 x + 12} \right) - 24 x = x \left( \dfrac{30x}{13 x + 12} \right)$

$36(30x) -24 x(13x + 12) = 30x^2$

$1080 x - 312 x^2- 288 x = 30x^2$

$x(792 - 342 x)= 0$

$x = 0 \textrm{ or } x=792/342 = \dfrac{44}{19}$

We have to rule out x=0 because it's in the denominator.

$y = \dfrac{30x}{13 x + 12} = \dfrac{30(44/19)}{13(44/19)+12}$

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Answer: (44/19, 33/20)

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2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

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2 years ago

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lukranit [14]

Answer:

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3 years ago

Which expression has a value of 23?

DaniilM [7]

A) $7 - (-16) = \fbox {23}$

B) $-3 - 20 = \fbox {-23}$

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D) $-18 - (-5) = \fbox {-13}$

You were correct, the exact answer is A. The others do not equal 23 besides that one. Good job!

6 0

3 years ago

Read 2 more answers