Answer:
Logic for a program
Explanation:
//Here ind = index
//declare the number
number ind
number sum
number avg
number SIZE = 20
number num[SIZE] = {0,0,0,0,0,0,0,0,0,0
,0,0,0,0,0,0,0,0,0,0}
getReady()
while ind < SIZE
getNumbers()
stop
getReady()
ind = 0
sum = 0
return
getNumbers()
cout<< “Enter a number for position ”, ind
input numbers[ind]
sum = sum + numbers[ind]
ind = ind + 1
return
;
finishUp()
avg = sum/SIZE
ind = 0
while ind < SIZE
output numbers[ind], avg – numbers[index]
ind = ind + 1
return
Modify the program in 2a
number index
number sum
number avg
number actualSize
number SIZE = 10
number number[SIZE] = 0
Answer:
<em>C++</em>
////////////////////////////////////////////////////////////////////////////////////////////////////////
#include <iostream>
#include <vector>
using namespace std;
int main() {
vector<int> v;
int n = 1;
while (n != 0) {
cout<<"Enter an integer, the input ends if it is 0: ";
cin>>n;
v.push_back(n);
}
cout<<endl;
///////////////////////////////////////////////////////////
int sum = 0;
int num_positives = 0, num_negatives = 0;
for (int i=0; i<v.size()-1; i++) {
if (v[i] > 0)
++num_positives;
else
++num_negatives;
sum = sum + v[i];
}
//////////////////////////////////////////////////////////
cout<<"The number of positives is "<<num_positives<<endl;
cout<<"The number of negatives is "<<num_negatives<<endl;
cout<<"The total is "<<sum<<endl;
cout<<"The average is "<<(float)sum/(v.size()-1);
///////////////////////////////////////////////////////////
return 0;
}
Answer:Analog component signals are comprised of three signals, analog R′G′B′ or YPbPr. Referred to as 480i (since there are typically 480 active scan lines per frame and they are interlaced), the frame rate is usually 29.97 Hz (30/1.001) for compatibility with (M) NTSC timing.
Explanation:
