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4 years ago

How to solve a quadratic equation?

1 answer:

3 0

In order to solve a quadratic equation first put all the terms on one side of the equal sign the factor them out, solve for each equation check by original equation

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What actions did colonists take to protest the Townshend Acts?

brilliants [131]

Answer:

The Townshend Acts would use the revenue raised by the duties to pay the salaries of colonial governors and judges, ensuring the loyalty of America's governmental officials to the British Crown. However, these policies prompted colonists to take action by boycotting British goods.

-Hope this helps :)

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%7Bx%7D%5E%7B%20log_%7B3%7D%28x%29%20%7D%20%20%3D%2081%20%7Bx%7D%5E%7B3%7D%20" id="TexFormula1

BlackZzzverrR [31]

Answer:

x=81 or 1/3

Step-by-step explanation:

$x^\log_3(x)} =81x^3\\\log_3(x^{\log_3(x)})=\log_3(81x^3)\\\(\log_3x)(\log_3x)=\log_381+\log_3x^3\\(\log_3x)^2=3\log_3x^+4\\\\Let u=\log_3x\\\\u^2-3u-4=0\\(u-4)(u+1)=0\\u=4 \\4=\log_3x\\x=3^4=81\\\\u=-1\\-1=\log_3x\\x=3^{-1}=1/3$

3 0

3 years ago

Anumeha is mowing the lawns for a summer job. For every mowing job, she charges and initial fee of $10 plus a constant fee for e

ExtremeBDS [4]

Answer:

F(t) = 10 +5t

Step-by-step explanation:

Income equals the initial fee plus the hours worked times the hourly rate

We know the initial fee = 10

hours = t

hourly rate =r

F(t) = 10 + r*t

We know a 5 hour job is 35 dollars

35 = 10 + r*5

Subtract 10 from each side

35-10 = 10-10 +5r

25 = 5r

Divide by 5

25/5 = 5r/5

5 =r

The hourly rate is 5

F(t) = 10 +5t

8 0

3 years ago

Solve for v.<br> 4v = 676

SpyIntel [72]

Answer:

v=169

Step-by-step explanation:

$4v=676$

Divide by 4.

$v=\frac{676}{4}$

$v=169$

6 0

4 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago