Answer:
Use the formula y-y1=m(x-x1) <---memorize this. The m here is the slope.
Step-by-step explanation:
The equation is in y=mx+b form
Remember mx=slope and b=y-intercept
The question wants you to find the equation that is Parallel to y=-3x-2 and passes through (-3,-3)=(x1,y1)
Parallel=same slope -3x
So now all that's left is to plug into the equation.
y-(-3)=-3(x-(-3))
y+3=-3(x+3) ----> positive - a negative = positive so x-(-x)=x+x
y+3=-3x-9 ----> distribute like terms(subtract 3 from 3 and 3 from -9)
y=-3x-12 - This is your answer, you can check by graphing it.
Could i get Brainlest? thx :)
Now we look at the common denominator.
It is x(x + 2)(x - 2).
x cannot be zero, -2 or 2 because that would cause a zero in the denominator.
Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.
Answer: x = 8
Answer:
<em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>2</em><em>*</em><em>3</em><em>=</em><em>3</em><em>6</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer:
y - 3 = (5/3)(x - 6)
Step-by-step explanation:
The usual first step is to determine the slope of the given line.
In this case the slope is -3/5.
A line perpendicular to this given line would have a slope of 5/3, which is the negative reciprocal of -3/5.
This new line goes thru (6, 3) and has a slope of 5/3. Thus, the equation of the line in point-slope form is
y - 3 = (5/3)(x - 6)
Double check that you have copied the problem down correctly. The slope of the line represented by -3x - 5y = 17 is neither 2 nor -2; it is -3/5, and so the slope of a line perpendicular to -3x - 5y = 17 is +5/3.
