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gayaneshka [121]
3 years ago
11

a company made one of the largest single purchase of long distance telephone time in history. it purchased 49 million minutes at

a total cost of $ 1,470,000. if the company resells the phone time at an average of 6 cents per minute, how much profit will it make on the purchase?
Mathematics
1 answer:
mestny [16]3 years ago
3 0
Sales price is
49,000,000×0.06
=2,940,000

Profit
2,940,000−1,470,000
=1,470,000...answer
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50 points for answer.
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Answer:

Point C: (4, 0)

Step-by-step explanation:

Parallelograms are quadrilaterals with two pairs of parallel sides, this means they will have the same slope between two line segments.

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Answer:

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p_v =2*P(Z  

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Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

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The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

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