Sqrt 363 - 3 sqrt27
= sqrt(121* 3) - 3 sqrt (9*3)
= sqrt 121* sqrt3 - 3 * sqrt 9 * sqrt3
= 11 sqrt3 - 3* 3 sqrt3
= 11 sqrt3 - 9 sqrt3
= 2 sqrt3 Answer
Answer:
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In order for the product of some numbers to end in a zero, the prime factors of ... So 1 x 2 x 3 x ... x 98 x 99 x 100 (AKA 100!) has 24 zeroes at the end
Answer:
Hence x = y = 2
Step-by-step explanation:
Using the SOH CAH TOA identity
Hypotenuse = 2√2
Opposite = x
theta = 45
Sin theta = opp/hyp
Sin 45 =x/2√2
1/√2 = x/2√2
x = 2√2 * 1/√2
x = 2
To get y we will use the pythagoras theorem;
(2√2)² = x² +y²
(2√2)² = 2²+y²
8 = 4 + y²
y² = 8-4
y² = 4
y = √4
y = 2
Hence x = y = 2