All categories

3 years ago

Find the x-intercept of the graph of each equation. a. 3x+2y=7 b. 2x+3y=7

Mathematics

2 answers:

stepladder [879]3 years ago

6 0

A.3x+2y=7

Have a nice day.

ahrayia [7]3 years ago

3 0

A. is 7/3
b. is 7/2
you do this by making y=0 and then working through what remains

You might be interested in

Ejercicio1:

Lemur [1.5K]

Answer:

Cost of car including VAT = $17,700

Step-by-step explanation:

Given:

Cost of car without VAT = $15,000

Rate of VAT = 18%

Find:

Cost of car including VAT

Computation:

Cost of VAT = Cost of car without VAT x Rate of VAT

Cost of VAT = 15,000 x 18%

Cost of VAT = 15,000 x 18

Cost of VAT = $2,700

Cost of car including VAT = Cost of car without VAT + Cost of VAT

Cost of car including VAT = 15.000 + 2700

Cost of car including VAT = $17,700

5 0

2 years ago

Can I PLEASE get some help?

Leviafan [203]

Well 1/40 is 0.025 so that should be the write fraction to use

4 0

3 years ago

Read 2 more answers

A baby’s t-shirt requires 2/9 yards of fabric. How many t-shirts can be made from 38 yards?

Bess [88]

8 4/9 hope this helps!!!

3 0

3 years ago

I need this fast thank you! :)

Alex Ar [27]

Answer:

Step-by-step explanation:

Hope this helps! Good Luck!

3 0

3 years ago

Read 2 more answers

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago