So, the definite integral 
Given that
We find
<h3>Definite integrals </h3>
Definite integrals are integral values that are obtained by integrating a function between two values.
So, 
So, ![\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7B%284%20-%206x%5E%7B2%7D%20%29%7D%20%5C%2C%20dx%20%3D%20%5Cint%5Climits%5E1_0%20%7B4%7D%20%5C%2C%20dx%20-%20%5Cint%5Climits%5E1_0%20%7B6x%5E%7B2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%3D%20%204%5Bx%5D%5E%7B1%7D_%7B0%7D%20%20%20%20-%20%5Cint%5Climits%5E1_0%20%7B6x%5E%7B2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%3D%20%204%5Bx%5D%5E%7B1%7D_%7B0%7D%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%3D%204%5B1%20-%200%5D%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx%5C%5C%3D%204%5B1%5D%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx%5C%5C%3D%204%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx)
Since
,
Substituting this into the equation the equation, we have
So,
Learn more about definite integrals here:
brainly.com/question/17074932
Answer:
y= 1/4x+5
Step-by-step explanation:
y=mx+c
to calculate gradient: change in y/change in x
-3/-12 = 0.25
y = 1/4x+c
4 * 1/4 = 1
6-1 = 5
c= 5
Totally:
y= 1/4x+5
Answer:
2/3 = 0.6666666666666667 or just 67%.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The first 9 stands for 90,000 and the second for 9 000 so the first 9 is worth
90,000 / 9,000 equals 10 times the second one.
Answer:
C and D
Step-by-step explanation:
