Question

Use the Quadratic Formula to solve the equation. (Enter your answers as a comma-separated list.) 13x^2 +1 = -10

Answer 1

Step-by-step explanation:

The given quadratic equation is :

$13x^2 +1 = -10x\\\\or\\\\13x^2+10x+1=0$

The formula to solve a quadratic equation is :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Put a = 13, b = 10 and c = 1

So,

$x=\dfrac{-10\pm \sqrt{10^2-4(13)(1)} }{2(13)}\\\\x=-0.118, -0.651$

Hence, this is the required solution.