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2 years ago

Does 12/15 and 8\10 have the same value

Mathematics

2 answers:

Rudik [331]2 years ago

6 0

Answer:

as 12 and 15 can be divided by 3, I'll simplify it to 4/5 and 8 and 10 can be divided by 2 and it'll be 4/5 so they have the same value, see that by simplifying it

bazaltina [42]2 years ago

6 0

Answer:

yes

Step-by-step explanation:

12 divided by 15 equals 0.8

8 divided by 10 equals 0.8

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Write a proportion to answer the question.

goblinko [34]

Step-by-step explanation:

1. divide .5 from 100 and you will end up with 200.

2. multiply 200 by 8 giving you the answer 1600

to make sure the answer is correct you multiply the .5 percent by 1600 leaving you with 8

8 0

3 years ago

Austin borrowed money from a credit union for 4 years and was charged simple interest at an annual rate of 5% the total interest

Reika [66]

Given:

Rate of simple interest = 5%

Time = 4 years

Total interest = $160

To find:

The amount borrowed by Austin from a credit union.

Solution:

The formula for simple interest is:

$I=\dfrac{P\times r\times t}{100}$

Where, P is principal, r is the rate of interest and t is the number of years.

Putting $I=160,r=5,t=4$ in the above formula, we get

$160=\dfrac{P\times 5\times 4}{100}$

$160=\dfrac{20P}{100}$

$160=\dfrac{P}{5}$

Multiply both sides by 5.

$800=P$

Therefore, Austin borrowed $800 from a credit union for 4 years.

8 0

2 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$