Answer:
Step-by-step explanation:
Okay, so attached is a diagram of the triangle we are solving. Because buildings are almost always perpendicular (90 degrees) to the ground, it is a right triangle.
You can now use the pythagorean theorem with the sides to fill in the other side:
a^2+ b^2= c^2
5^2 + b^2= 22^2
25+b^2=484
b^2= 459
b=21.42
Okay, so for slope you need 2 points- think of the wall as your y axis, and the ground as your x axis. The ladder is the line.
Your first point is (-5,0) because the bottom of the ladder is touching the ground (no y movement) and the bottom of the ladder is 5 feet from the base of the wall and ground (origin).
The second point is going to be (0, 21.42) because that is the height of the wall where the ladder is touching (x is at origin). The 21.42 is positive, because you can't have negative height.
Okay so far? :)
(-5,0) and (0, 21.42)
(x1, y1) and (x2, y2)
slope= (y2-y1)/(x2-x1)
slope= (21.42-0)/ (0-(-5)) ---- becomes positive
slope= 4.284
(Note: slope could also be negative if you put the ladder on the other side of the wall- 5 would become positive... google "positive vs negative slopes" for more info)
Hopefully that answers your question!
Answer:
5. 8/6x + 2
6. -4x - 2
7. y=3
Step-by-step explanation:
we conclude that the center of the circle is the point (-5, 0).
<h3>How to find the center of the circle equation?</h3>
The equation of a circle with a center (a, b) and a radius R is given by:

Here we are given the equation:

Completing squares, we get:

Now we can add and subtract 25 to get:

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).
If you want to learn more about circles:
brainly.com/question/1559324
#SPJ1
Answer: C) exactly one triangle
<u>Step-by-step explanation:</u>
Given: ∠A = 45°, ∠B = 65°, side c = 4 cm
By the Triangle Sum Theorem, ∠C = 70°
Now you have a proportion so you can use the Law of Sines to find the exact length of side a and of side b.

Thus, there is exactly one triangle.
8 feet, because 10^{2} - 6^{2} = 64;
\sqrt{64} = 8[tex]