Solve for x in the equation I need help ASAP

Mathematics

2 answers:

natita [175]4 years ago

7 0

Answer:

Step-by-step explanation:

Given

2x² + 3x - 7 = x² + 5x + 39

Subtract x² + 5x + 39 from both sides

x² - 2x - 46 = 0 ← in standard form

with a = 1, b = - 2, c = - 46

Solve for x using the quadratic formula

x = (- (- 2) ± $\sqrt{(-2)^2-(4(1)(-46)}$ ) / 2

= ( 2 ± $\sqrt{4+184}$ ) / 2

= ( 2 ± $\sqrt{188}$ ) / 2

= ( 2 ± 2 $\sqrt{47}$ ) / 2

= 1 ± $\sqrt{47}$

DedPeter [7]4 years ago

4 0

The answer is D

You just move all numbers to the left and set it equal to 0
And then you add all same variables together
After that you use the quadratic formula

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use the graphing calculator to graph the quadratic function y = x2 − 5x − 36. Which value is a solution of 0 = x2 − 5x − 36?

daser333 [38]

The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.

The graph is attached below.

We are given a quadratic function.
A polynomial equation of degree two in one variable is a quadratic equation.
The function given to us is :
y = x² - 5x - 36
We need to find the solution of the quadratic function.
To find the roots, let y = 0.
x² - 5x - 36 = 0
Use the quadratic formula.
In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
x = [-b±√b²-4ac]/2a
x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
x = (5 ± √25 + 144)/2
x = (5 ± √169)/2
x = (5 ± 13)/2
x = 9 or x = -4