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Shalnov [3]
3 years ago
11

Convert the equation from Standard to General form Can somebody help me ASAP

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:x squred+ y squared +4y-21=25

Step-by-step explanation:

You might be interested in
Graph the solution on the number line |x-3| <5
Anettt [7]

Answer:

-2<x<8

see below for graph

Step-by-step explanation:

First, we need to solve the inequality.

Inequality: |x-3|<5

Split into two equations:

x-3<5

x-3>-5 (notice how the sign is flipped when we make the number negative)

let's start with x-3<5

add 3 to both sides

x<8

now

x-3>-5

add 3 to both sides

x>-2

The graph is below

the intersection is the solution.

Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)

the equation is -2<x<8

Hope this helps!

8 0
3 years ago
Mr Smith takes orders from 12 people. 8 people want coffee and 6 people want donuts. how many people want coffee and donuts?
PIT_PIT [208]

Answer:

2

Step-by-step explanation:

8 + 6 - 12 = 2

5 0
3 years ago
What is;<br><br> 3+7+2-1+12-8÷19=
Novay_Z [31]

Answer:

22.5 repeated

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Ken started a savings account for school. He plans on spending 10% of the money he earns for leisure activities. He needs to hav
KiRa [710]

Answer:

He must earn $2,400 to cover both leisure and $2,160 for school expenses.

Step-by-step explanation:

Let the total amount Ken must earn be k.  Then 10% of that would cover leisure activities and the remaining 90% specifically for school expenses.

Then 0.90k = $2,160, and k = $2,400.

He must earn $2,400 to cover both leisure and $2,160 for school expenses.

7 0
3 years ago
The table shows the relationship between the cost of renting a car from the Wrecko Car Rental Company and the number of days for
Fudgin [204]

Answer:

The cost of renting the car for 20 days is $481

Step-by-step explanation:

The table of values can be formed as follows;

Day,   Cost

1,         $44

2,        $67

3,        $90

4,        $113

7,        $182

10,      $251

From the given values and the scatter plot, there is a straight line relationship between the cost and the number of days of rental of a car.

The line of best fit is therefore a straight line and from the constant increase in cost ($23) for each extra day of rental, it is possible to find the slope, m, of the data as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

(x₁, y,) and (x₂, y₂) can be taken as (1, $44) and (3, $90) respectively to give;

Slope, \, m =\dfrac{90-44}{3-1} = \dfrac{46}{2} = 23 \ as \ stated \ above

The equation in slope and intercept form is therefore, y  - 44 = 23×(x - 1), which gives;

y - 44 = 23·x - 23

y = 23·x - 23 + 44 = 23·x + 21

The cost of renting the car for 20 days is then;

10×23 + 21 = $481

The cost of renting the car for 20 days = $481.

5 0
3 years ago
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