The distributed property is one of the most frequently used properties in math. In general, this term refers to the distribution property of multiplication. The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.
Constant is something continuously occurring over a period of time.
Coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
Term is either a single number or variable, or numbers and variable multiplied together. Terms are separated by + or - signs.
Identity Property of Municipality states that any time you multiply a number by 1, the results, or product, is that original number.
Identity Property if Addition is always zero.
Like terms are terms whose variables are the same. In other words, terms that are "like"
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Answer:
25
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 175cm
Standard deviation = 6 cm
Percentage of students below 163 cm
163 = 175 - 2*6
So 163 is two standard deviations below the mean.
By the Empirical rule, 95% of the heights are within 2 standard deviations of the mean. The other 100-95 = 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of them are more than 2 standard deviations below the mean(so below 163cm) and 2.5% are more than two standard deviations above the mean.
2.5% of the students have heights less than 163cm.
Out of 1000
0.025*1000 = 25
25 is the answer
Find the inverse of f(x)=2x-3.
1) replace "f(x)" with "y." Then y=2x-3.
2) interchange x and y. Then x=2y-3. x+3
3) solve this result for y. Then 2y=x+3, or y=----------------
2
-1 -1 x+3
4) replace y with f (x): f (x) = ---------
2
This is the procedure, with the answer given.
Answer:
a). V = 14.6208 litres : b). = 0.29844 Litres/sec
Step-by-step explanation:
a).
Step 1.
Volume when one half of rod is inserted = (50/2)*(2.2) = 55cm³
Step 2.
As we know that,
V = (ρVIΔT) / (ρL) where = 290 - 4.2 = 285.8K
sepecififc heat of aluminum = 0.215 cal/g
density = 2.7 g/cm3
= (2.7)*(55)*(0.215)*(285.8) / (0.125)*(20900)*(1/4186)
V = 14.6208 litres
b).
Step 1.
As we know that
P = kA(dT/dx) = 31*2.2*[(290-4.2)/25]
= 779.6624 W
Step 2.
Now, approximate boil rate of helium is:
P/ρL= [(779.6624)*(10^3g/kg)] / [(0.125)*(20900)]
= 0.29844 Litres/sec