Answer:
the perimeter is 28 and the area is 49
Step-by-step explanation:
a square has equals sides and i counted seven on each side for the perimeter. you multiply seven by seven to find the area
Answer:
B=112 degrees A=68 degrees and C=68 degrees
Step-by-step explanation:
the opposite angle of the 112-degree angle is the angle on the top left of the page, this means both of the angles are the same. You can then tell that that angle is the same as the one across from it because it shows on the page. You can then figure out the opposite angle which is B so that means angle B is equal to 112 degrees. To figure out angle A you can just do 180 minus the angle B which is 112 degrees. You now know angle A which is 68 degrees, now to find the angle C you just have to notise that angle C is the opposite angle of angle A. This means that algle C is also 68 degrees.
The correct answer is B. So for A, 8m is smaller than 12 m. For B, 20 m is Bigger. For C, Find how many meters is 1 centimeter, the answer is 1 cm : 12m, the meter is not bigger than 12, but the same, so C is wrong. For D, divide both sides by 3 to find 1 CM, the answer is 1 cm : 5 m, it is wrong.
1 kilometer = 10000 meters
1 kilometer = 100000 centimeters
I can so more and explain more is you want Hope it helps
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simplifying
we get 
Step-by-step explanation:
We need to simplify: 
Solving:
Applying the rule:
log a + log b = log(ab)

So, simplifying
we get 
Keywords: Simplifying Logarithms
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