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4 years ago

If one bag of red grapes costs $2, how many bags can we buy with $18?

Mathematics

2 answers:

const2013 [10]4 years ago

8 0

You would be able to get 9 bags of grapes.
2 * 9 = 18

Hope this helps!

mars1129 [50]4 years ago

8 0

Answer:

9 bags

Step-by-step explanation:

The question asks how many bags can we buy with $18 knowing that each bag cost $2

So we need to <u>divide the $18 by the cost of each bag</u> to calculate the number of bags we can buy:

number of bags = $18 / $2 per bag = 9 bags

This calculation can also be expressed as:

number of bags = 18 dollars × $\frac{1 bag}{2 dollars}$ = 9 bags

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You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of you

Firlakuza [10]

1.3*3=3.90
3.90*35=136.50
136.50 is all you need to provide at least three of the most expensive items.
You still have 13.50 left over

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3 years ago

Read 2 more answers

List the factors of 15 and 30. Indicate which factors are common to both numbers and the Greatest Common Factor (GCF).

monitta

Factors of 15 . . . 1, 3, 5, 15

Factors of 30 . . . 1, 2, 3, 5, 6, 10, 15, 30

Common factors (numbers on both lists) . . . 1, 3, 5, 15

Greatest common factor (biggest number on both lists) . . . 15

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3 years ago

Ryan has a board that is 5 feet long. how many 1/3-foot sections can he cut from this board?

labwork [276]

Ryan can cut 15 pieces from the board

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3 years ago

One strange phenomenon that sometimes occurs at U.S. airport security gates is that an otherwise law-abiding passenger is caught

valentinak56 [21]

Answer:

c. 0.16

Step-by-step explanation:

For each passenger there are only two possible outcomes. Either they are caught with a gun, or they are not. The probability of a passenger being caught with a gun is independent from other passengers. So we use the binomial probability distribution to solve this question.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 3000000, p = 0.00001$

$\mu = E(X) = np = 3000000*0.00001 = 30$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{3000000*0.00001*(1-0.00001)} = 5.48$

What is the probability that tomorrow more than 35 domestic passengers will accidentally get caught with a gun at the airport?

This probability is 1 subtracted by the pvalue of Z when X = 35. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{35 - 30}{5.48}$

$Z = 0.91$

$Z = 0.91$ has a pvalue of 0.8186

1 - 0.8186 = 0.1814.

The closest answer is:

c. 0.16

8 0

3 years ago

A fractal tree starts with a single tree branch (the trunk). At each stage, each new branch from the previous stage grows two mo

AleksandrR [38]

A) New branch in:

2nd stage=2

3rd stage=4

4th stage=8

which can be listed as 2,4,8,...

Here,

2nd term/1st term=4/2=2

3rd term/2nd term=8/4=2

Since common ratio is 2, the given sequence is geometric sequence.

b) The required function is,

B(n)=2^(n-1)

{just put n=1,2,3.. here to check if it gives accurate no of branches in each step or not}

where n is stage number

c)Using above function to calculate total no of branches growing out in the 8th stage,

B(8)=2^(8-1)=2^7=128

3 0

3 years ago