Answer:
A ≈ $500
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Compounded Interest Rate: A = P(1 + r/n)ⁿˣ
- A is final amount
- P is initial (principle) amount
- r is rate
- n is number of compounds
- x is number of years
Step-by-step explanation:
<u>Step 1: Define</u>
P = 230
r = 0.063
n = 365
x = 12
<u>Step 2: Solve for </u><em><u>A</u></em>
- Substitute: A = 230(1 + 0.063/365)³⁶⁵⁽¹²⁾
- Divide: A = 230(1 + 0.000173)³⁶⁵⁽¹²⁾
- Multiply: A = 230(1 + 0.000173)⁴³⁸⁰
- Add: A = 230(1.00017)⁴³⁸⁰
- Exponents: A = 230(2.1296)
- Multiply: A = 489.808
Answer:
<h2>
204π units²</h2>
Step-by-step explanation:
The lateral area of the cylinder includes both the side and the ends.
The area of the side can be found by calculating the circumference of the cylinder and multiplying that by the height: A = 2π(6 units )(11 units) = 132π units².
The area of one end of this cylinder can be found by applying the "area of a circle" formula: A = πr². Here, with r = 6 units, A = π(6 units)² = 36π units². Since the cylinder has two ends, the total area of the ends is thus 2(36π units) = 72π units.
The total lateral area of the cylinder is thus 72π units² + 132π units², or 204π units²
50 states, 4 start with W (Washington, West Virgina, Wisconsin, Wyoming)
So its 8%
Recall that the interior angles of a quadrilateral add up to 360 degrees.
1) Let x be the measure of the missing angle, then we can set the following equation:
Solving for x we get:
2) Let y be the measure of the missing angle, then we can set the following equation:
Solving for y we get:
Answer:
1) 100 degrees.
2) 58 degrees.
Answer:
DL/dt = 17 mph
Step-by-step explanation:
The ships and the port shape a right triangle
Ship going west ( x-direction) is traveling at 15 mph
Ship going north (y-direction) is traveling at 10 mph
The distance L between ships is:
L² = x² + y²
Tacking derivatives on both sides of the equation with respect to time
we get
2*L*DL/dt = 2*x*Dx/dt + 2*y*Dy/dt (1)
In that equation we know:
Dx/dt = 15 mph
Dy/dt = 10 mph
At the moment ship traveling from the east is at 3 miles from the port
then x = 3 m and the other ship is at 4 miles north
then by Pythagoras theorem
L = √ 3² + 4² L = 5
By substitution in equation 1
2*5*DL/dt = 2*3*15 + 2*4*10
10* DL/dt = 90 + 80
DL/dt = 170 / 10
DL/dt = 17 mph
