The speed is the change in position divided by the time.
There are four intervals where the speed is uniform:
1) from 0 to 0,5 hours
2) from 0,5 hours to 3 hours
3) from 3 to 4 hours
4) from 4 to 7 hours
We are asked to say the average speed during the interval in which J. is traveling the fastest.
That is where the is more inclined, and that happen in the last interval. There the speed is tha change in position / the time =
(200 -0)miles/3hours = 67 mph.
If you are not sure that this is the fastest speed, you can calculate the speed in the other intervals in the same way and compare.
Multiply the original DE by xy:
xy2(1+x2y4+1−−−−−−−√)dx+2x2ydy=0(1)
Let v=xy2, so that dv=y2dx+2xydy. Then (1) becomes
x(y2dx+2xydy)+xy2x2y4+1−−−−−−−√dxxdv+vv2+1−−−−−√dx=0=0
This final equation is easily recognized as separable:
dxxln|x|+CKxvKx2y2−1K2x4y4−2Kx2y2y2=−dvvv2+1−−−−−√=ln∣∣∣v2+1−−−−−√+1v∣∣∣=v2+1−−−−−√+1=x2y4+1−−−−−−−√=x2y4=2KK2x2−1integrate both sides
18 necklaces in 3 hours
18/3 = 6
6 necklaces in 1 hour
hope this helps
Answer:
15
Step-by-step explanation:
First divide: 6/10 ( to get a rate)
Next multiply: 25*0.6
Final answer: 15