The Foldgers Black Silk K-cup coffee pods weigh on average .28 ounces with a standard deviation of .05 ounces. Answer each of th

Question

3 years ago

9

The Foldgers Black Silk K-cup coffee pods weigh on average .28 ounces with a standard deviation of .05 ounces. Answer each of th

e questions.
68%, 2.5%, 81.5%, 95%, 41-42, 20-21, 16%, 84%, 121-122, 5%, 87-88, 64, 35-36
What percentage of K-cups can be expected to fall within 2 Standard Deviations of the mean?

What is the probability that a K-cup will have more than .33 ounces?

Sam's club sells K-cups in a box of 128. How many of them will weigh less than .23 ounces?

K-cups that are more than 2 SD below the mean are considered to be to "weak". What percentage of K-cup are considered to "weak"

In a standard box of 44 k-cups, how many will weigh between .23 and .38 ounces

The ideal weight for K-cups are within 1 SD of the mean, how many of the Sam's Club box of K-cups are ideal?

Mathematics

1 answer:

iragen [17] · Answer 1 · 2022-11-30T13:48:19+03:00

Using the Empirical Rule, it is found that:

95% of K-cups can be expected to fall within 2 Standard Deviations of the mean.
0.16 = 16% probability that a K-cup will have more than .33 ounces.
20 of them will weight less than 0.23 ounces.
2.5% of K-cups are considered weak.
36 will weigh between 0.23 and 0.38 ounces.
30 of the Sam's Club box of K-cups are ideal.

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem:

The mean is of 0.28 ounces.
The standard deviation is of 0.05 ounces.

First, by the Empirical Rule, 95% of K-cups can be expected to fall within 2 Standard Deviations of the mean.

0.33 ounces is one standard deviation above the mean.

68% of the measures are between 0.23 and 0.33 ounces.
The normal distribution is symmetric, which means that of the remaining 100 - 68 = 32%, 16% are less than 0.23 ounces and 16% are more than 0.33 ounces, thus:

0.16 = 16% probability that a K-cup will have more than .33 ounces.

16% weigh less than 0.23 ounces. Out of 128:

$0.16(128) = 20$

20 of them will weight less than 0.23 ounces.

5% of the measures are more than 2 SD from the mean. Due to the symmetry of the normal distribution, 2.5% are more than 2 SD below the mean, thus, 2.5% of K-cups are considered weak.