The number of different ways that three speakers can be selected is 10 ways
Given the names of choice to be Ben, Will, Stewart, Hilary, and Kate. This means that we have a total of 5 name choices.
If the members of students activities are to select three speakers among these people, the number of ways this can be done is by using the combination rule as shown;
From the question, n = 5 and r = 3. On substituting
Hence the number of different ways that three speakers can be selected is 10 ways.
Learn more here: brainly.com/question/24145745
Answer:
(ab - 6)(2ab + 5)
Step-by-step explanation:
Assuming you require the expression factorised.
2a²b² - 7ab - 30
Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term
product = 2 × - 30 = - 60 and sum = - 7
The factors are - 12 and + 5
Use these factors to split the ab- term
= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )
= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term
= (ab - 6)(2ab + 5) ← in factored form
B = bees, w = wasps, x = hornets
b + w + x = 184
b = 3x - 9
w = x + 28
(3x - 9) + (x + 28) + x = 184...combine like terms
5x + 19 = 184
5x = 184 - 19
5x = 165
x = 165/5
x = 33 <== points scored by Hornets
Answer:
<em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>C</em><em> </em><em>1</em><em>/</em><em>3</em><em>2</em><em> </em><em>I</em><em>b</em>
Step-by-step explanation:
hope it helps
The value of three in 6,300 is 3,000 because it is in the thousands place. The three in 530 is in the hundreds place making the value of three 300. Hope that this helps you :D
