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Stella [2.4K]
4 years ago
5

which of the following are valid probability distributions for a discrete random variable? check all that apply

Mathematics
2 answers:
djverab [1.8K]4 years ago
3 0
A. <span>0.16 + 0.193 + 0.222 + 0.233 + 0.067 + 0.125 = 84
</span>probabilities are all between 0 and 1 but does not add to 1.
<span>B. 0.35+0.18+ 0.21+ 0.06+ 0.17+ 0.03 = 1
</span>probabilities are all between 0 and 1 and also <span>add to 1.
</span><span>C. (0.01) 11+ (0.01) 12+ (0.01) 13 = 0.11+0.12+0.13 =0.36
</span>probabilities are all between 0 and 1 but does not add to 1.
D. 0.16+0.12+ 0.02+ 0.08+ 0.22+ 0.05+ 0.15+ 0.02+ 0.18 = 1
probabilities are all between 0 and 1 and also add to 1.
E. 0.12-0.02+0.18+0.08+0.15+0.05+0.16+0.27+0.02+ 0.36 -0.15 -0.22 =1
probabilities are all between 0 and 1 and also <span>add to 1.</span>
Olegator [25]4 years ago
3 0

Answer:

I think it's D.

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Se vendieron un total de 430 boletos para la obra de teatro escolar. Los boletos eran o de adulto o de estudiante. Se vendieron
BartSMP [9]

Resolviendo un sistema de ecuaciones, veremos que se vendieron 250 boletos de adulto.

<h3>¿Cuántos boletos de adulto fueron vendidos?</h3>

Definamos las variables:

  • x = boletos de adulto vendidos.
  • y = boletos de estudiantes vendidos.

Se vendieron un total de 430 boletos, entonces:

x + y = 430

Y se vendieron 70 boletos de estudiante menos que boletos de adulto:

y = x - 70

Tenemos el sistema de ecuaciones:

x + y = 430

y = x - 70

Para resolverlo, podemos reemplazar la segunda ecuación en la primera:

x + y = 430

x + (x - 70) = 430

2x = 430 + 70 = 500

x = 500/2 = 250

Se vendieron 250 boletos de adulto.

Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

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2 years ago
Sin(a+b).cos(a-b) = sinacosa + sinbcosb
Rainbow [258]
Sin (A + B) = sin A cos B + cos A Sin B 
<span>Cos (A - B) = cos A cos B + sin A sin B </span>

<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>

<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>

<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved 

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3 years ago
Hello i am having trouble and i would love some one to help me
myrzilka [38]

Answer:

Your answer is 7.5 loaves were baked that morning.

Step-by-step explanation:

To find the percent of a number, you drop the percent sign, and move the decimal 2 places to the left. Then you multiply that by the other number.


Hope this helps!

Let me know if you still don't understand!



~Courtney

6 0
4 years ago
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Jimmy sold a book for $69.95 on Cheggs.com. The state had to added a 8% tax his book. How much was
kari74 [83]

Answer:

$5.60

Step-by-step explanation:

Multiply the price of your book, $69.95 by the tax .08

69.95 x 0.08 = 5.596, rounded up to 5.60

3 0
3 years ago
What is 3y^2+3(4y^2-2)?
egoroff_w [7]

It's a 2nd degree algebraic expression in ' y '.

It's pretty messy in this form, and it can be substantially cleaned up.

Looking at just the second term, we can remove the parentheses:

3 (4y² - 2) = 12y² - 6

Now we can put that into the original expression ... 3y² + 12y² - 6

then combine the y² terms:    <em>15y² - 6</em> .

If you want to go one step farther, we can factor it:  <em>3(5y² - 2) </em>

3 0
4 years ago
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