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Stella [2.4K]
3 years ago
5

which of the following are valid probability distributions for a discrete random variable? check all that apply

Mathematics
2 answers:
djverab [1.8K]3 years ago
3 0
A. <span>0.16 + 0.193 + 0.222 + 0.233 + 0.067 + 0.125 = 84
</span>probabilities are all between 0 and 1 but does not add to 1.
<span>B. 0.35+0.18+ 0.21+ 0.06+ 0.17+ 0.03 = 1
</span>probabilities are all between 0 and 1 and also <span>add to 1.
</span><span>C. (0.01) 11+ (0.01) 12+ (0.01) 13 = 0.11+0.12+0.13 =0.36
</span>probabilities are all between 0 and 1 but does not add to 1.
D. 0.16+0.12+ 0.02+ 0.08+ 0.22+ 0.05+ 0.15+ 0.02+ 0.18 = 1
probabilities are all between 0 and 1 and also add to 1.
E. 0.12-0.02+0.18+0.08+0.15+0.05+0.16+0.27+0.02+ 0.36 -0.15 -0.22 =1
probabilities are all between 0 and 1 and also <span>add to 1.</span>
Olegator [25]3 years ago
3 0

Answer:

I think it's D.

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The answer is C, hope this helps
6 0
3 years ago
Express the volume of the box as a<br>polynomial in the variable x
Whitepunk [10]

The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

<h3>How to determine the volume?</h3>

The complete question is added as an attachment

From the attached image, we have:

Length = 12 - 2x

Width = 7 - 2x

Height = x

The volume is calculated as:

Volume = Length * Width * Height

Substitute the known values in the above equation

Volume = (12 - 2x) * (7 - 2x) * x

This gives

Volume = x(12 - 2x)(7 - 2x)

Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

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7 0
2 years ago
Please answer asap!!!!!
kherson [118]

Step-by-step explanation:

The equation of a circle can be the expanded form of

\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)

2

+(y−b)

2

=r

2

where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.

Here, the equation of the circle is,

\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}

⟹

⟹

⟹

⟹

x

2

+y

2

+10x−4y−20

x

2

+y

2

+10x−4y+25+4−49

x

2

+y

2

+10x−4y+25+4

x

2

+10x+25+y

2

−4y+4

(x+5)

2

+(y−2)

2

=

=

=

=

=

0

0

49

49

7

2

From this, we get two things:

\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}

1.

2.

Center of the circle is (−5, 2).

Radius of the circle is 7 units.

Hence the radius is 7 units.

4 0
2 years ago
18/X=2.4/28 find X plz help
yulyashka [42]
Cross multiply

18 / X = 2.4 / 28
so
18 * 28 = X (2.4)
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504 = X * 2.4
then divide by 2.4
X = 210
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3 years ago
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Consider the expression.
lorasvet [3.4K]
Two less than 5 times a number is 9
5 0
2 years ago
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