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3 years ago

Why does the theft of the Tai-me represent the decline of the Kiowa people?

Mathematics

2 answers:

babunello [35]3 years ago

7 0

Answer:

Step-by-step explanation:

your answer choice would be B

have a wonderful day;)

Ne4ueva [31]3 years ago

7 0

2. The Tai-me symbolized the Collective Strength of the Kiowa people

Took the quiz :)

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Jorge is asked to build a box in the shape of a rectangular prism. Its height will be 2 cm more than its width. The sum of the l

Rasek [7]

Answer:

Step-by-step explanation:

h=x+2

w=x

h+w=20

x+x+2=20

2x=18

x=9

w=x=9

width = 9

4 0

2 years ago

H hhdhfjfjfjjfjjfjfjjfj

Fiesta28 [93]

Answer:

um so like I think it's 420

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2 years ago

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How do I get 1/4 of $3.20

leva [86]

" of " means multiply

1/4 * 3.20/1...and just multiply....(1 * 3.20) / (4 * 1) = 3.20/4 = 0.8
or
1/4 = 0.25.....0.25(3.20) = 0.8

8 0

3 years ago

Read 2 more answers

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

What is the anser ro this question 11+(20-13)

noname [10]

20-13=7+11=18 is the answer
Don't forget to thank me

7 0

2 years ago

Read 2 more answers