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never [62]
3 years ago
9

Find the midpoint of the segment with the following endpoints. (10,2) and (5, -7)

Mathematics
1 answer:
Sati [7]3 years ago
4 0

Answer:

(7.5 , -2.5)

Step-by-step explanation:

Sub the values into this formula

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3.844 times 106 kilometers
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A random sample of ten professional athletes produced the following data where x is the number of endorsements the player has an
lukranit [14]

ŷ= 1.795x +2.195 is the equation for the line of best fit for the data

<h3>How to use regression to find the equation for the line of best fit?</h3>

Consider the table in the image attached:

∑x = 29,  ∑y = 74, ∑x²= 125, ∑xy = 288,  n = 10 (number data points)

The linear regression equation is of the form:

ŷ = ax + b

where a and b are the slope and y-intercept respectively

a = ( n∑xy -(∑x)(∑y) ) / ( n∑x² - (∑x)² )

a  = (10×288 - 29×74) / ( 10×125-29² )

  = 2880-2146 / 1250-841

  = 734/409

  = 1.795

x' =  ∑x/n

x' = 29/10 = 2.9

y' = ∑y/n

y' = 74/10 = 7.4

b = y' - ax'

b = 7.4 - 1.795×2.9

  = 7.4 - 5.2055

  = 2.195

ŷ = ax + b

ŷ= 1.795x +2.195

Therefore,  the equation for the line of best fit for the data is ŷ= 1.795x +2.195

Learn more about regression equation on:

brainly.com/question/29394257

#SPJ1

3 0
1 year ago
rick won 27 tickets playing a game. to get a prize, he needs to win at least 30 tickets. how many more tickets can he win to get
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He needs 3 Tickets to Win a Prize.27×2 is... And that's ur Answer
8 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

7 0
3 years ago
A quadratic equation is shown below:
Mariulka [41]

hello : 

<span>help :
<span>the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a</span>
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions</span>

7 0
3 years ago
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