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Ivanshal [37]
4 years ago
12

Which of the following exponential equations could describe the graph shown below

Mathematics
2 answers:
snow_lady [41]4 years ago
6 0
Since the line crosses the Y axis below 1 and raises going to the right it would be y=1/3(4)^x
tangare [24]4 years ago
6 0

Answer:

3. y=\frac{1}{4}(\frac{1}{2} )^{x}

Step-by-step explanation:

To find the equation best suited to the graph, look at the y-intercept, which is where x = 0 and y = \frac{1}{4}. Use each formula and replace the x with zero to determine the y-intercept of each formula:

1) y=2(5)^{0} =2

2)y=\frac{1}{3}(4)^{x0}=\frac{1}{3}

3)y=\frac{1}{4} (\frac{1}{2} )^{0} =\frac{1}{4}

4)y=5(\frac{1}{4})^{0}=5

The only likely equation is number 3

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It would be B. 68

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3 years ago
A. Complete the table if y varies
serious [3.7K]

Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

<em>y = 30 </em>

<em>y = 30 k = 6</em>

<em>y = 30 k = 6x = 5</em>

<em>y = 30 k = 6x = 5Equation: y = 6x</em>

y = k × x

y = 10 × 8

y = 80

So,

<em>y = 80 </em>

<em>y = 80 k = 10</em>

<em>y = 80 k = 10x = 8</em>

<em>y = 80 k = 10x = 8Equation: y = 10x</em>

y = 3x

18 = 3x

x = 18/3

x = 6

So,

<em>y = 18</em>

<em>y = 18k = 3</em>

<em>y = 18k = 3x = 6</em>

<em>y = 18k = 3x = 6Equation: y = 3x</em>

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

<em>y = 72</em>

<em>y = 72k = 2</em>

<em>y = 72k = 2x = 6</em>

<em>y = 72k = 2x = 6Equation: y = 2x²</em>

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

<em>y = 5</em>

<em>y = 5k = 30</em>

<em>y = 5k = 30x = 6</em>

<em>y = 5k = 30x = 6Equation: y = 30/x</em>

y = k/x

y = 36/4

y = 9

So,

<em>y = 9</em>

<em>y = 9k = 36</em>

<em>y = 9k = 36x = 4</em>

<em>y = 9k = 36x = 4Equation: y = 36/x</em>

y = 60/x

20 = 60/x

20x = 60

x = 60/20

x = 3

So,

<em>y = 20</em>

<em>y = 20k = 60</em>

<em>y = 20k = 60x = 3</em>

<em>y = 20k = 60x = 3Equation: y = 60/x</em>

y = 24/x

y = 24/12

y = 2

So,

<em>y = 2</em>

<em>y = 2k = 24</em>

<em>y = 2k = 24x = 12</em>

<em>y = 2k = 24x = 12Equation: y = 24/x</em>

Read more:

brainly.com/question/472621

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Could I have assistance, please...?<br><br> Find the domain of the square-root function.
andrezito [222]

Answer:

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Step-by-step explanation:

domain of f(x) :

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x≥-8

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