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masha68 [24]
3 years ago
15

Use common factors to write two fractions equivalent to 6/42

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

19.) 14/18, 21/27  

20.) 3/21, 2/14  

21.) 6  

22.)8/9  

25.) 36/73  

26.) 1/3=.33 2/8=.25 Eric is more successful

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Joel can drive his car 450 miles at a steady speed using 15 gallons of gasoline. Making rate table showing the number of miles y
harkovskaia [24]
I hope this helps!! Don’t mind the 20 mph at the top. That was from another problem I was helping someone else on.

4 0
3 years ago
Decrease R1400 in the Ratio 7:3​
goldfiish [28.3K]

Answer:

Step-by-step explanation:

It's hard to tell what you mean. I'm going to assume you mean that you want what is left to be 3/7 less.

1400 - 3/7 1400 = 1400 - 600 = 800

8 0
3 years ago
Mikaela placed a frame around a print that measures 10 inches by 10 inches. The area of just the frame itself is 69 square inche
olchik [2.2K]

Answer:

1.5 in

Step-by-step explanation:

Let x be the width of the frame.

Side of print=10 in

Area of frame=69 square in

We have to find the width of the frame.

Side of frame=10+x+x=10+2x

Area of square=(side)^2

By using the formula

Area of print=10\times 10=100in^2

Area of frame with print=(10+2x)^2

Area of frame=Area of frame with print-Area of print

69=(10+2x)^2-100

(10+2x)^2=69+100=169

(10+2x)=\sqrt{169}=\pm 13

10+2x=13

Because Side is always positive.

2x=13-10=3

x=\frac{3}{2}=1.5

Hence, width of frame=1.5 in

3 0
3 years ago
what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil
dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
3 years ago
What is the image point of (6, 7) after a translation left 5 units and up 3
BlackZzzverrR [31]

Answer:

the new point would be (1, 10).

Step-by-step explanation:

if you start with the point (6, 7) and go left 5 units and up 3 units, then the new point you land on is (1, 10) as you can see in the picture below. hope this helped!

6 0
3 years ago
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