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3 years ago

Why 3^-7 x 3^7 = 1. . Someone please

Mathematics

1 answer:

irina [24]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

3^-7 x 3^7 = 1

The negative exponents put it in the denominator

1/ 3*3*3*3*3*3*3 * (3*3*3*3*3*3*3) = 1

The 3's cancel leaving

1/1 = 1

1=1

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If you could answer these, that would be great

Afina-wow [57]

Answer:

Aww thats cute

Step-by-step explanation:

5 0

2 years ago

Doris uses 8square pieces of fabric to make one scarf. Each side of a square piece of fabric is 1/4 foot in length. Doris can bu

Semmy [17]

Scarf area is 8 small fabric area
8 x 0.25 x 0.25 =0.5.
7 scarf area would be
7 x 0.5 = 3.5
new fabric (large ) area is
2 x 0.25 = 0.5
7 scarf area divide by new fabric area
3.5 divide by 0.5 = 7 large pieces

4 0

2 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

1 year ago

Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circ

RSB [31]

Answer:

146°

Step-by-step explanation:

Points A and B are the endpoints of an arc of a circle. Chords are drawn from the two endpoints to a third point, C, on the circle. Given m arch AB=64° and ⦣ABC=73°, m ⦣ABC=__ ° and m arch AC=__ °.

Solution:

Given that:

arc AB = 64° and ⦣ABC=73°

The Central Angle Theorem states that the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points. The inscribed angle is any point along the outer arc AB and the two points A and B.

Therefore arc AC is the central angle of ⦣ABC. Using the central angle theorem gives:

arc AC = 2 * ⦣ABC

substituting:

arc AC = 2 * 73

arc AC = 146°

8 0

2 years ago

Simplify <br> Rewrite the expression in the form z^n<br><br> z^5•z^6= ______

gtnhenbr [62]

Answer:

z²^30

Step-by-step explanation:

This is it enjoy.

4 0

3 years ago