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Dafna1 [17]
3 years ago
6

Help with #3 please

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0
M < ABC = 2 * m <DBA
8x - 6 = 2x + 5
6x = 11
x = 11/6  or 1 5/6  answer
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Which function is best represented by this graph?
12345 [234]
I believe the answer is C
4 0
2 years ago
Read 2 more answers
A silo is a composite of a cylindrical tower with a cone for a roof. What is the volume of the silo if the radius of the base is
kirza4 [7]

Answer:

The answer is b. 343,480.8ft

Step-by-step explanation:

I thought it was c at first because I forgot to add the volume of the cone.

The equation for the volume of a cylinder is V=π×r²×h

The solution would look like V=π40²×65=326725.8

The equation for the volume of a cone is V=1/3πr²×h

The solution would look like V=1/3π×40²×10=16755

Adding the two volumes would equal 326725.8±16755= 343480.8

5 0
3 years ago
Please hurry. it's geometry.
Ainat [17]

That would be option A as the angles  and sides  ( the AS) have already been stated.

7 0
2 years ago
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
3 years ago
If the problem says x=5 ,did it give you a input or output?
Thepotemich [5.8K]
It gave you the input because it is telling you what x is
8 0
2 years ago
Read 2 more answers
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