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WARRIOR [948]
3 years ago
8

Factorise 6xy - 15y2​

Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

3y(2x - 5y).

Step-by-step explanation:

6xy is basically 2 * 3 * x * y.

-15y^2 is basically -1 * 3 * 5 * y * y.

Something both have in common are a 3 and a y.

So, we have...

3 * y(2 * x - 1 * 5 *y)

= 3y(2x - 5y).

Hope this helps!

goldfiish [28.3K]3 years ago
8 0

Answer:

The answer is 3y( 2x - 5y)

Step-by-step explanation:

6xy - 15y²

Factor out the LCF out

That's

3y( 2x - 5y)

Hope this helps you

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I need the answer ASAP! Please help me!
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Answer:

Please check the explanation.

Step-by-step explanation:

<u>Determining the length of BC</u>

From the diagram, it is clear that

  • The point B is located at (-8, 10) and point C is located at (8, 10)

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

<u>Determining the length of CD</u>

Given

  • C (8, 10)
  • D (2, -2)

The distance between C(8, 10) and D(2, -2)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}

      =\sqrt{6^2+12^2}

      =\sqrt{36+144}

      =\sqrt{180}

      =\sqrt{36\times 5}

      =6\sqrt{5}

Thus, the length of CD =6\sqrt{5} units

<u>Determining the length of ED</u>

Given

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The distance between E(-8, -4) and D(2, -2)

ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}

      =\sqrt{10^2+2^2}

      =\sqrt{100+4}

      =\sqrt{104}

       =\sqrt{26\times \:4}

        =2\sqrt{26}

Thus, the length of ED =2\sqrt{26} units

<u>Determining the length of EB</u>

From the diagram, it is clear that

  • The point E is located at (-8, -4) and the point B is located at (-8, 10)

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

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