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2 years ago

Find the area of the polygon. 29 yd 16 yd 6 yd 4 yd 6 yd

Mathematics

1 answer:

Verizon [17]2 years ago

8 0

29yd is the answer to your question

You might be interested in

What is yhe answer?????

myrzilka [38]

161%

Step-by-step explanation:

They are asking percentage so we know we going to ×100%

4943 AS A PERCENTAGE OF 3076

$\frac{4943}{3076} \times 100$

161%

8 0

2 years ago

Graph the function defined by the parametric equations x = 2t3 – 3t and y = -2t2 – 1 over the parameter

den301095 [7]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

A graphing calculator does this nicely.

4 0

2 years ago

I need help with this pls use 3.14 with or the formula with area

Leni [432]

Rectangle:
A=l(w)

A=12(6)

A=72cm^2

Semicircle:
r=6/2

r=3

A=(3.14(r)^2(1/2)

A=3.14(3)^2(1/2)

A=3.14(9)(1/2)

A=14.13cm^2

A=14.1cm^2

Total area: 72cm^2 + 14.1cm^2 = 86.1cm^2

6 0

2 years ago

Solve for t. 4=2+2/5t

maxonik [38]

T=5

4=2+2/5t
Subtract 2 from both sides.
2=2/5t
Multiply both sides by 5/2.
t=5

8 0

2 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

2 years ago