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german
3 years ago
8

Lisa and Jen are each reading a different 250-page book consisting of 10 chapters. Which statistics would be helpful in determin

ing whose book shows the greater variability in the chapter length? Check ALL that apply.(may be more than one or all)
A.the median of the chapter lengths in each book
B.the mean of the chapter lengths in each book
C.the interquartile range of the chapter lengths in each book
D.the range of chapter lengths in each book
Mathematics
2 answers:
lawyer [7]3 years ago
3 0
D the range is the correct answer 
Dahasolnce [82]3 years ago
3 0

3, and 4 are the correct choices i just did the test on edgunuity 2020

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Calcula el volumen de una pirámide de altura 3cm cuya base es un cuadrado de lado 4cm
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AnsweR IS 12

Step-by-step explanation:

4 X 3 IS 12

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4 years ago
How much is one melon if 3 sell for $1.98 ?
Sonbull [250]

Answer: $0.66


Step-by-step explanation: Just divide 3 / $1.98 and you will get $0.66.

Fairly simple, But the only thing I don't understand is why a melon is on sale for $0.66. Thats CHEAP! Give me 100 :)


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3 years ago
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Identify the distance between points (−3,−6,7) and (−9,5,−4), and identify the midpoint of the segment for which these are the e
melisa1 [442]

Step-by-step explanation:

LET THE Point 1 A and point 2 is B

(AB) ^2=(-9-(-3))^2+ (5-(-6))^2+(-4-7)^2=278

AB=16.67 length unit

Midpoint

X=-9-3/2 =-6

Y=5-6/2=-0.5

Z=-4+7/2=-1.5

4 0
3 years ago
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here is a image. 6th grade problem i in 6th grade. Please do part A and part B for problem 1 and also please do problem 2 so ASA
Andrej [43]

I have no idea what to do in problem 1

but I will do problem 2

A. 2⁵ = 32 (2×2×2×2×2=32)

B. 4³/2 = 32 (4×4×4=64 and then 64÷2=32

the others are not equal to 32

3 0
3 years ago
Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i
Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em>  and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558

(b) What is the probability that at least 4 arrive during a 1-hour period?

\bf P(X\geq4)=1-P(X

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}

and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But

\bf P(X

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0
4 years ago
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