Answer:
the basic functions performed by living organisms for their survival and body maintenence are called life process.
Explanation:
life process require energy which is provided by nutrition .
basic life processes are : nutrition , respiration , transportation , excretion .
Answer:
It's important to not touch the sides or the bottom of the test tube with the thermometer because touching it to the sides or bottom of the test tube fractures the glass and does not allow for correct temperature measurements.
The wrinkled pea will have two recessive alleles on the locus.
Explanation:
Two forms of same gene are called alleles of that gene.
The allele that expresses itself under heterozygous condition is called the Dominant allele.
The recessive allele can express itself only if they are under homozygous combination i.e. both the alleles on homologous chromosome are recessive.
Here wrinkled pea is a recessive trait and if it is expressed in the phenotype then the genotype of the plant must be homozygous for the recessive allele.
Considering the child's age and symptoms, it appears that this is an allergic reaction. It can be inferred that among the options, the food most likely to trigger these symptoms is peanut butter.
Peanut butter, in addition to having added sugar, hydrogenated or semi-hydrogenated fats, sodium and other additives, has proteins that our bodies recognize as "foreign" causing our immune system to react.
Peanut allergy is usually discovered in the early years of life, due to its high consumption in childhood, and especially affects babies and children who have asthma, rhinitis and sinus problems.
Answer:
The possible blood types of their children are: type AB (iAiB), type A (iAi), type B (iBi), type O (ii)
Explanation:
Blood type in humans is controlled by a gene with multiple alleles. Alleles iA and iB are dominant over allele i but co-dominant. The following blood types are encoded by the following alleles:
Blood type AB - iAiB
Blood type A - iAiA or iAi
Blood type B - iBiB or iBi
Blood type O - ii
According to this question, a man who has type B blood has children with a woman who has type A blood. They are both heterozygous, meaning that the man's genotype is "iBi" while the woman's genotype is "iAi". Both parents will produce gametes as follows:
iBi = iB and i
iAi = iA and I
Using these gametes in a punnet square (see attached image), the following possible blood types are produced in the offsprings:
- type AB (iAiB)
- type A (iAi)
- type B (iBi)
- type O (ii)
