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Nikitich [7]
4 years ago
10

What graph shows the sequence 9,3,-3,-9

Mathematics
1 answer:
Alex17521 [72]4 years ago
8 0
Is there a picture with the question
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Factorize x squared - 1x +10 =0
Natalka [10]

Answer:

no solution exists:

Step-by-step explanation:

x²−1x+10=0

Step 1: Simplify both sides of the equation.

x²−x+10=0

Step 2: Subtract 10 from both sides.

x²−x+10−10=0−10

x²−x=−10

Step 3: The coefficient of -x is -1. Let b=-1.

Then we need to add (b/2)^2=1/4 to both sides to complete the square.

Add 1/4 to both sides.

x²−x+ 1/4=−10+ 1/4

x²−x+ 1/4=−39 /4

Step 4: Factor left side.

(x  -1/2)² = −39 /4

Step 5: Take square root.

x  −1 /2 =±√ −39 /4

Step 6: Add 1/2 to both sides.

x  =−1/2  + 1/2 = 1/2 ±√ -39/4

x = 1/2 ±√ -39/4

No real solutions.

6 0
4 years ago
Pls help me I don’t know this!!!
Mamont248 [21]
Angle G is 144 degrees because it makes a linear pair with angle 36
4 0
3 years ago
Read 2 more answers
If one root is the square root of the other in the equation 8 + mx + 27x^2 = 0, find the value of m​
ICE Princess25 [194]

Answer:

Step-by-step explanation:

6 0
3 years ago
Here is an expression: 3 • 2t
leva [86]

Answer:

1. 6

2. 24

Step-by-step explanation:

Substitute in the values for <em>t</em> and solve the expression.

3 0
3 years ago
Read 2 more answers
What is the least possible degree of a polynomial that has roots -5, 1+4i, and -4i
N76 [4]
If complex coefficients are allowed, the answer is 3.

If the polynomial must have real coefficients, then each complex root comes as a pair of complex conjugate roots.

Root -5 is real, so that is 1 root, and degree 1.

Root 1 + 4i is complex, so it must come with its complex conjugate, 1 - 4i. This adds 2 roots to the polynomial, and now we're up to degree 3.

Root -4i is also complex. It also must come with its complex conjugate, 4i. That adds two more roots, and the degree is 5.

Answer: The least possible degree is 5 with real coefficients.
3 0
3 years ago
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