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Rom4ik [11]
3 years ago
9

PLEASE HELP graph the functions

Mathematics
1 answer:
Andrei [34K]3 years ago
5 0

Answer:

f

Step-by-step explanation:

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The solution of a certain differential equation is of the form y(t)=aexp(7t)+bexp(11t), where a and b are constants. The solutio
Solnce55 [7]

Answer:

Step-by-step explanation:

Given that the solution of a certain differential equation is of the form

y(t) = ae^{7t} +be^{11t}

Use the initial conditions

i) y(0) =1

1=a(1)+b(1)\\a+b=1 ... I

ii) y'(0) = 4

Find derivative of y first and then substitute

y'(t) = 7ae^{7t} +11be^{11t}\\y'(0) =7a+11b \\7a+11b =4 ...II

Now using I and II we solve for a and b

Substitute b = 1-a in II

7a+11(1-a) = 4\\-4a+11 =4\\-4a =-7\\a = 1.75 \\b = -0.75

Hence solution is

y(t) = 1.75e^{7t} -0.75e^{11t}

8 0
2 years ago
Read 2 more answers
Analyze the graph below and complete the instructions as follows.
zhannawk [14.2K]

Answer:

Option A:

x^2 + (y - 2)^2 = 9

Step-by-step explanation:

We know that the equation for a circle centered in the point (a, b) and of radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

So the first thing we need to find is the center of the circle.

We can see that the center is at:

x = 0

y = 2

Then the center is at the point (0, 2)

Now we want our circle to pass through point 2, located at a distance of 2 units from the radius of the first circle.

So the distance between the center and point 2 is 2 units plus the radius of the smaller circle:

And the radius of the smaller circle is one unit.

Then, the radius of a circle centered at (0, 2) that passes through point 2 is:

R = 1 + 2 = 3

Then we have a circle centered at (0, 2) and of radius R = 3

Replacing these in the equation for a circle we get:

(x - 0)^2 + (y - 2)^2 = 3^2

x^2 + (y - 2)^2 = 9

The correct option is A

5 0
3 years ago
Can anybody help me with this question?
Bogdan [553]
For number 16 we need to write the data as a ratio then convert to a unit rate (amount per 1)...

308/14 = x/1

Cross multiply

14x = 308
x = 308/14
x = 22

So the fuel efficiency is
22 miles per 1 gallon or

22/1

For number 17, since the car was driven at 48 mph, we just have to divide distance driven by speed to get how long it took...

288 miles ÷ 48 mph =

6 hours
6 0
3 years ago
What is the solution to this equation x/-2 =18
svetlana [45]

x = - 36

multiply both sides of the equation by - 2

x = (- 2)× 18 = - 36



4 0
3 years ago
Which equation represents a proportional relationship?
Sergeu [11.5K]
There is no equations 
7 0
3 years ago
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