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Jlenok [28]
3 years ago
9

Can someone help with these

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

y=4^x\Rightarrow\begin{array}{c|cc}x&y\\in put&o utput\\1&4\\2&16\\3&64\\4&256\\5&1024\\\end{array}\\\\y=-3^x\Rightarrow\begin{array}{c|cc}x&y\\in put&o utput\\1&-3\\2&-9\\3&-27\\4&-81\\5&-243\end{array}\\\\

Step-by-step explanation:

Put the values of x (input) to the formulas of the functions

y=4^x\\\\x=1\to y=4^1=4\\\\x=2\to y=4^2=16\\\\x=3\to y=4^3=64\\\\x=4\to y=4^4=256\\\\x=5\to y=4^5=1024\\===================\\\\y=-3^x\\\\x=1\to y=-3^1=-3\\\\x=2\to y=-3^2=-9\\\\x=3\to y=-3^3=-27\\\\x=4\to y=-3^4=-81\\\\x=5\to y=-3^5=-243

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Select the correct answer. Which point lies on a circle with a radius of 5 units and center at P(6, 1)? A. Q(1, 11) B. R(2, 4) C
jasenka [17]

Answer:

T(9,-2)

Step-by-step explanation:

The circle has radius 5 units and center P(6,1).

The equation of this circle is

(x-6)^2+(y-1)^2=5^2

(x-6)^2+(y-1)^2=25

If Q(1,11) lies on this circle, then it must satisfy its equation.

(1-6)^2+(11-1)^2=25

(-5)^2+(10)^2=25

25+100=25, this statement is false.

If R(2,4) lies on this circle, then it must satisfy its equation.

(2-6)^2+(4-1)^2=25

(-4)^2+(3)^2=25

16+9=25, this statement is false.

If S(4,-4) lies on this circle, then it must satisfy its equation.

(4-6)^2+(-4-1)^2=25

(-2)^2+(-5)^2=25

4+25=25, this statement is false.

If T(9,-2) lies on this circle, then it must satisfy its equation.

(9-6)^2+(-2-1)^2=25

(4)^2+(-3)^2=25

16+9=25, this statement is TRUE.

The correct answer is D

6 0
3 years ago
Read 2 more answers
The sum of four consecutive integers is 286
Rudik [331]
Solve it like this. x + (x+1) + (x+2) + (x+3) = 286
 4x + 6= 286
4x= 280 
x = 70
70+71+72+73=286 
4 0
4 years ago
Read 2 more answers
marie plans to trick are treat with maury friend whitney it takes marie 20 minutes to put on maury costume 15 minutes to eat din
Valentin [98]

Answer: 5:50

Step-by-step explanation:

20+15+5=40. 6:30 minus 40 min is 5:50

8 0
2 years ago
HELP ME PLZ! :3
sveta [45]
Part A:
y=mx+b
621=83(7)+b

Part B:
621=83(7)+b
621=581+b
621-581=b
b=40
Insurance cost is 40$


6 0
3 years ago
How many subsets of five elements each can be made from a set of seven elements?
Alina [70]
<span>When creating a subset of 5 elements from 7 elements, order should not matter. Therefore, we use the combination formula over the permutation formula. The combination formula given n elements total and r elements used is n! / [r!*(n-r)!]. Substituting 7 for n and 5 for r, we get: 7! / (5!*2!) = 7*6 / 2 = 21 21 subsets can be created</span>
8 0
3 years ago
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