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Diano4ka-milaya [45]
3 years ago
15

How many subsets of five elements each can be made from a set of seven elements?

Mathematics
1 answer:
Alina [70]3 years ago
8 0
<span>When creating a subset of 5 elements from 7 elements, order should not matter. Therefore, we use the combination formula over the permutation formula. The combination formula given n elements total and r elements used is n! / [r!*(n-r)!]. Substituting 7 for n and 5 for r, we get: 7! / (5!*2!) = 7*6 / 2 = 21 21 subsets can be created</span>
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Ann [662]
I think the anwser is 17,887
7 0
3 years ago
there are 8 students at each of 4 rounds of tables in the cafeteria. there are 64 students at long tables. use the bar model to
Tomtit [17]

Step-by-step explanation:

there should be at least

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3 years ago
ACTIVITY 1
aleksklad [387]

Answer:

Question A:

1. 1/2  = 0.5 (Terminating)

2. 5/6  = 0.833333.. (Repeating)

3. 21/3 = 1.6666666.. (Repeating)

Question B:

1. 0.6  = 3/5

2. 1.25  = 5/4 = 1 1/4

3. 0.125 = 1/8

Step-by-step explanation:

A. Write the fraction or mixed number as a terminating or repeating decimal.

In order to convert a fraction into decimal, the numerator has to be divided by denominator.

1. 1/2

The answer is: 0.5 which is a terminating decimal.

2. 5/6

The answer is: 0.833333.. which is a repeating decimal.

3. 2 1/3 (assuming the question is this)

2\frac{1}{3} = \frac{7}{6} = 1.6666666..

The answer is 1.6666666.. which is a repeating decimal.

B. Write the terminating decimal as fraction or mixed number i n simplest form.

1. 0.6

0.6 = \frac{6}{10} = \frac{3}{5}

2. 1.25

1.25 = \frac{125}{100} = \frac{5}{4} = 1\frac{1}{4}

3. 0.125

0.125 = \frac{125}{1000} = \frac{5}{40} = \frac{1}{8}

Hence,

Question A:

1. 1/2  = 0.5 (Terminating)

2. 5/6  = 0.833333.. (Repeating)

3. 21/3 = 1.6666666.. (Repeating)

Question B:

1. 0.6  = 3/5

2. 1.25  = 5/4 = 1 1/4

3. 0.125 = 1/8

7 0
3 years ago
How can addition properties help me add whole numbers
Bas_tet [7]

Answer:

There are four addition properties that help to add whole numbers :

For any  whole number a, b, and c ;

1. <u>Closure property of addition </u>-   a+b

For example:

2+3=5

4+3=7

We can conclude that if we add any two whole number , we get another whole number.

2. <u>Associative property of addition</u>- when any whole number or variable are added, then that can be grouped in different way without changing result

a+(b+c)=(a+b)+c

For example:  

2+(3+4)=(2+3)+4

3.<u> </u><u>Commutative property of addition</u>- when any  whole number or variable are added, then the order changed without changing the result.

a+b=b+a

For example: 2+3=3+2

4. <u>Identity property of addition</u>- when 0 is added to a whole number or variable , the result is the same variable or number.

a+0=0+a

For example: 3+0=0+3

0 is called an Identity for addition of whole numbers.


3 0
3 years ago
What is the explicit formula for this sequence?
kati45 [8]

<em>Greetings from Brasil...</em>

With the recursive formula, lets build the sequence:

A1 = 4

A2 = A1 - 7

A3 = A2 - 7

A4 = A3 - 7

A5 = A4 - 7

(...)

But pay attention to A3....

A3 = A2 - 7   but  A2 = A1 - 7 , so rewriting A3

A3 = (A1 - 7) - 7 ⇒ A3 = A1 + 2.(- 7)

A4 = A3 - 7 ⇒ A4 = [(A1 - 7) - 7] - 7 = A1 + 3.(- 7)

A5 =  {[(A1 - 7) - 7] - 7} - 7 = A5 + 4.(- 7)  

so

<h3>An = A1 + (n - 1).(- 7)</h3>

6 0
3 years ago
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