Question

A commercial jet can fly 868 miles in 2 hours with a tailwind but only 792 miles in 2 hours into a headwind. Find the speed of the jet in still air and the speed of the wind.

Answer 1

Answer:

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

x -----> the speed of the wind in miles per hour

y ----> the speed of the jet in still air in miles per hour

we know that

With a tailwind

$y+x=\frac{868}{2}$

$y+x=434$ ----> equation A

With a headwind

$y-x=\frac{792}{2}$

$y-x=396$ ----> equation B

solve the system of equations A and B by elimination

Adds equation A and equation B

$y+x=434\\y-x=396\\------\\y+y=434+396\\2y=830\\y=415$

Find the value of x

$y+x=434$

$415+x=434$

$x=434-415$

$x=19$

therefore

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

Answer 2

Answer:

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph