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Vera_Pavlovna [14]
3 years ago
15

Can someone help me with #1 and #2 please!

Mathematics
2 answers:
arlik [135]3 years ago
6 0
The game is fair because its the same amount of possible outcomes for both participants 

Brilliant_brown [7]3 years ago
4 0
The first one is fair and the second one is fair as well
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Factorise 7a + 14b + ax + 2bx<br>​
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Gwar [14]
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3 years ago
Find the coordinates of the point which divides the join of (-1,7) and (4.-3) in the ratio 2:3 ??
d1i1m1o1n [39]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h2>

Find the coordinates of the point which divides the join of (-1,7) and (4,-3) in the ratio 2:3 ?

<h2><u>Solution</u>:-</h2>

Let the given points be A(-1,7) and B(4,-3)

Now,

Let the point be P(x, y) which divides AB in the ratio 2:3

Here,

<h3>{ \bf  x \: = \frac{m_1 x_2 \: + \: m_1 x_1}{m_1 \: + \: m_2}}</h3>

Where,

m_1 = 2 , m_2 = 3

x_1 = -1 , x_2 = 4

\therefore Putting values we get,

x = \frac{2 \: × \: 4 \: + \: 3 \: × \: -1}{2 \: + \: 3}

x = \frac{8 \: - \: 3}{5}

x = \frac{5}{5}

x = 1

Now,

Finding y

<h3>{ \bf  y \: = \frac{m_1 y_2 \: + \: m_2 y_1}{m_1 \: + \: m_2}}</h3>

Where,

m_1 = 2 , m_2 = 3

x_1 = 7 , x_2 = -3

\therefore Putting values we get,

y = \frac{2 \: × \: -3 \: + \: 3 \: × \: 7}{2 \: + \: 3}

y = \frac{-6 \: + \: 21}{5}

y = \frac{15}{5}

y = 3

Hence x = 1, y = 3

So, the required point is P(x, y)

= P(1, 3)

<h3>The coordinates of the point is P(1, 3). [Answer]</h3>

_______________________________________

<u>N</u><u>o</u><u>t</u><u>e</u>:- Refer the attachment.

_______________________________________

5 0
3 years ago
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