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3 years ago

14

If it takes 558 gallons of gas to drive 18 miles how many miles can you drive with 18 gallons of gas?

2 answers:

sp2606 [1]3 years ago

7 0

Answer: 31

Step-by-step explanation: divide 558 by 18

Damm [24]3 years ago

7 0

Answer:

.5806

Step-by-step explanation:

its a ratio reduce 558/18 to 31/1 and set it equal to 18/x solve and u should get .5806

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Please help need someone’s help ASAP

xxTIMURxx [149]

your answer is D

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3 years ago

Read 2 more answers

I need plz help fast

Bad White [126]

Answer:

<h2>-4a²b³ (-6+ 7a³)</h2><h2 />

Step-by-step explanation:

24a²b³ - 28a⁵b³

apply exponential rule:

24a²b³ - 28a²a³b³

re-write 24 as 6*4 and -28 as 7*4

6*4a²b³ + 7*4a²a³b³

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-4a²b³ (-6+ 7a³)

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3 years ago

How do I solve these problems?

lesya [120]

$Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D$

$\log x=5.6-\log7.5\ \ \ \ |+\log7.5\\\\\log x+\log7.5=5.6\ \ \ \ |use\ \log x+\log y=\log (xy)\\\\\log(7.5x)=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\7.5x=10^{5.6}\ \ \ \ |:7.5\\\\\boxed{x=\dfrac{10^{5.6}}{7.5}}\in D$

5 0

3 years ago

A rectangle on a coordinate plane is translated 5 units up and 3 units to the left. Which rule describes the translation?

Svetradugi [14.3K]

Answer:

(x-3,y+5)

Step-by-step explanation:

5 units up would be written as: $y + 5$ .

3 units to the left would be $x - 3$ .

The rule that describes the translation of 5 units up and 3 units to the left would be:

$(x,y) \rightarrow (x-3,y+5)$

8 0

3 years ago

Chi square Daphne likes to ski at a resort that is open from December through April. According to a sign at the resort, 20, perc

Marat540 [252]

Answer:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

Step-by-step explanation:

The missing data for the random sample of 80 days between December and April with snowfall is:

Month Days

December 16

January 11

February 16

March 18

April 19

The Chi-square goodness of fit test would be used to determine whether the snow falls in Daphne's hometown followed the given distribution.

The hypothesis for the test can be defined as follows:

<em>H</em>₀: The snow falls in Daphne's hometown does not follow the given distribution.

<em>Hₐ</em>: The snow falls in Daphne's hometown followed the given distribution.

Assume that the significance level of the test is, <em>α</em> = 0.05.

The Chi-square test statistic is given by:

$\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}$

The value of Chi-square test statistic is computed in the Excel sheet below.

$\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}=8.383$

Compute the <em>p</em>-value as follows:

$\text{p-value}=P(\chi^{2}_{(4)}>8.383)=CHISQ.DIST.RT(8.383,4)=0.0785$

The <em>p</em>-value of the test is 0.0785.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

<em>p</em>-value = 0.0785 > <em>α</em> = 0.05.

The null hypothesis will not be rejected.

Conclusion:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

4 0

3 years ago