Answer:
Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.
Explanation:
You need to prepare 250. mL of a 0.550 M aqueous solution of sucrose, C12H22O11 (aq),
which is used frequently in biological experiments.
Based on your answer above, what is the value of x?
Solution:
A 0.550 M aqueous solution contains 0.550 mole of sucrose per liter of solution.
250 ml = 0.250 liter
Thus a 0.250 liter of a 0.550 M aqueous solution of sucrose contains 0.250 * 0.550 = 0.1375 mole of sucrose
Recall:
Mass = number of moles * mass of 1 mole
mass of 1 mole of C12H22O11
= 12(12) + 1(22) + 16(11)
= 144 + 22 + 176
= 342 grams
Mass = 0.1375 * 342 = 47.025 grams of sucrose.
Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.
