Answer:
b=5
Step-by-step explanation:
the answer is in the image above
Write the following equation in the general form Ax + By + C = 0.
2 answers:
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m ∠b = 133°, m ∠c = 47°, and m ∠d = 133°.
<h3>Further explanation</h3>Follow the attached picture. I sincerely hope that's precisely a correct illustration.
We will use a graph of two intersecting straight lines.
Note that m ∠a and m ∠c are vertical angles. Since vertical angles share the same measures, in other words always congruent, we see
We continue to determine m ∠b and m ∠d.
Note that m ∠b and m ∠d represent supplementary angles. Recall that supplementary angles add up to 180°.
Let us see the following steps.
Both sides subtracted by 47°.
Thus
Finally, note that m ∠b and m ∠d are vertical angles. Accordingly,
<u>Conclusion:</u>
- m ∠a = 47°
- m ∠b = 133°
- m ∠c = 47°
- m ∠d = 133°
<u>Notes:</u>
- Supplementary angles are two angles when they add up to 180°.
- Vertical angles are the angles opposite each other when two lines cross. Note that vertical angles are always congruent, or of equal measure.
- About the measure of the central angle brainly.com/question/2115496
- Undefined terms needed to define angles brainly.com/question/3717797
- Find out the measures of the two angles in a right triangle brainly.com/question/4302397
Keywords: m∠a = 47°, m∠b, m∠c, and m∠d, 133°, vertical angles, supplementary, 180°, congruent
Answer:
B) 4.07
Step-by-step explanation:
First we need to calculate the mean of all the data, which is the same as the mean of the means of each grade of gasoline:
Regular BelowRegular Premium SuperPremium
39.31 36.69 38.99 40.04
39.87 40.00 40.02 39.89
39.87 41.01 39.99 39.93
X1⁻=39.68 X2⁻= 39.23 X3⁻= 39.66 X4⁻= 39.95
Xgrand⁻ = (39.68+39.23+39.66+39.95)/4 = 39.63
Next we need to calculate the sum of squares within the group (SSW) and the sum of squares between the groups (SSB), and the respective degrees of freedom):
SSW = [ (39.31-39.68)² + (39.87-39.68)² + (39.87-39.68)² ] + [ (36.69-39.23)² + (40.00-39.23)² + (41.01-39.23)² ] + [ (38.99-39.66)² + (40.02-39.66)² + (39.99-39.66)² ] + [ (40.04-39.95)² + (39.89-39.95)² + (39.93-39.95)² ] = [0.2091] + [10.2129] + [0.6874] + [0.0121] = 11.12
SSW = 11.12
Degrees of freedom in this case is calculated by m(n-1), with m being the number of grades of gasoline (4) and n being the number of trial results for each one (3), so we would have 4(3-1) = 8 degrees of freedom
SSB = [ (39.68-39.63)² + (39.68-39.63)² + (39.68-39.63)²] + [ (39.23-39.63)² + (39.23-39.63)² + (39.23-39.63)² ] + [ (39.66-39.63)² + (39.66-39.63)² + (39.66-39.63)² ] + [ (39.95-39.63)² + (39.95-39.63)² +(39.95-39.63)² ] = [0.0075] + [0.48] + [0.0027] + [0.3072] = 0.7974
SSB = 0.80
For this case, the degrees of freedom are m-1, so we would have 4-1 = 3 degrees of freedom
Now we can establish the hypothesis for the test:
H0: μ1 = μ2 = μ3 = μ4
The null hypothesis states that the means of miles per gallon for each fuel are the same, indicating that the drade of gasoline does not make a difference, therefore our alternative hypothesis will be:
H1: the grade of gasoline does makes a difference
We will use the F statistic to test the hypothesis, which is calculated like follows:
F - statistic = (SSB/m-1) / (SSW/m(n-1)) = (0.80/3) / (11.12/8) = 0.19
We know that the level of significance we are using is α = 0.05, so to find the critical value F we need to look at some table of critical values for the F distribution for the 0.05 significance level (like the attached image). Then we just need to look fot the value that is located in the intersection between the degrees of freedom we have in the numerator (horizontal) and the denominator (vertical) of the statistic (3 and 8). That critical value is:
Fc = 4.07
