2 years ago

Please help mathhh assignment iready #6th grade

Mathematics

1 answer:

erastova [34]2 years ago

5 0

The number is the second one

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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg

Harman [31]

Answer:

$x=\frac{-5(+/-)\sqrt{5}} {2}$

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$f(x)=x^{2} +5x+5$

equate the function to zero

$x^{2} +5x+5=0$

$a=1\\b=5\\c=5$

substitute in the formula

$x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}$

$x=\frac{-5(+/-)\sqrt{5}} {2}$

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

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Answer:

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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