Step-by-step explanation:
the answer is 6
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Creo que es la A
prueba a traducirla i luego buscalo cual es la repuesta
Answer:
Assuming order does not matter, the probability of selecting all midsize cars is 0.000277373, or .
Step-by-step explanation:
First, we must find the n(Total arrangements of selections)=(8+15)C6
n(Total arrangements of selections)=23C6
n(Total arrangements of selections)=100,947
Second, we must find the n(Arrangements where all are midsize cars)=8C6
n(Arrangements where all are midsize cars)=28
To find the probability of selecting all midsize cars, we divide the n(Arrangements where all are midsize cars) by the n(Total arrangements of selections):
P(All midsize cars)=
P(All midsize cars)= =0.000277373.
I believe you have 6 bacteria 120 divided by 20 is 6 so
Total number of fruit = 5 + 5 + 4 = 14
P(A) = Probability of picking an apple on first pick = 5/14
P(B) = Probability of picking a peach on second pick = 5/13
P(C) = Probability of picking a peach on third pick = 4/12
All we have to do is multiply these probabilities:
5/14 * 5/13 * 4/12 = 25/546