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Maksim231197 [3]
1 year ago
11

Can someone please fill in blank ASAP

Mathematics
1 answer:
Annette [7]1 year ago
8 0

Answer:

The quotient is 48.

Step-by-step explanation:

Estimate the quotient using compatible numbers:

45 (or I guess any number close the answer above, not sure tbh)

Multiply the estimate by 21:

945

45*21

Is the estimate to high or too low?

too low

Adjust and continue until the product is 1008.

1008/21=48

Have a good day/evening! I hope my answer is correct!

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Please help me with this?
makvit [3.9K]
Number 2 is 25 that fors sure but i dont wanna give you the 3rd i dont know why bt i dont :/
8 0
4 years ago
Domain and range of the inequality y<√x+3 +1
Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

              y < \sqrt{x+3}+1

Related equation:

             y = \sqrt{x+3}+1

The equation defined as,

    x+3 > 0

    x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

    \sqrt{x+3} \geq 0

adding 1 on both sides, we get

  \sqrt{x+3} + 1 \geq  1

      y ≥ 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

6 0
2 years ago
How can you graph m(x)=5x and then compare it to f(x)=x?
erastovalidia [21]
Graph the line y=5x. Then graph the line y=x. Then look at them and describe in what ways they are the same or different.
5 0
4 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
I only need answer for part A.
Delvig [45]

Answer:

y= 1/6 x - 1 1/2

p-by-step explanation:

5 0
3 years ago
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