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LiRa [457]
3 years ago
7

The coin box of a vending machine contains $6.20 in dimes and quarters. There are 32 coins in all. How many of each kind are the

re?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0
Let d and q be the number of dimes and quarters respectively.

10 cents* d+ 25 cents* q = 620 cents ($6.20 = 620 cents)
⇒ 10d + 25q = 620 (1)

On the other hand, we have: d+ q= 32 (coins) (2)

From (1) and (2), we solve the set of equations.

The final answer is d= 12 coins and q= 20 coins.


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If 8% sales tax is charged on the sale price, what is the total with tax?
notsponge [240]
The total with tax is, you take the total given to you and multiply it by the decimal number of your percentage. Once you have gotten the number add that to your original number.
5 0
3 years ago
The line containing the median of the trapezoid whose vertices are R(-1, 5) , S(1, 8), T(7, -2), and U(2, 0).
bearhunter [10]

Answer:

y=-\dfrac{5}{3}x+6.5

Step-by-step explanation:

Given: trapezoid RSTU with vertices R(-1, 5), S(1, 8), T(7, -2), and U(2, 0).

Plot these points on the coordinate plane. As you can see, lines RU and ST are parallel lines and segments ST and RU are bases of the trapezoid.

The median of the trapezoid (the middle line) passes through the midpoints of the sides RS and TU. Find these midpoints:

M\left(\dfrac{x_S+x_R}{2},\dfrac{y_S+y_R}{2}\right)\Rightarrow M(0,6.5)\\ \\N\left(\dfrac{x_T+x_U}{2},\dfrac{y_T+y_U}{2}\right)\Rightarrow N(4.5,-1)

The equation of the line MN is

\dfrac{x-0}{4.5-0}=\dfrac{y-6.5}{-1-6.5}\\ \\\dfrac{x}{4.5}=\dfrac{y-6.5}{-7.5}\\ \\y=-\dfrac{5}{3}x+6.5

4 0
4 years ago
PLEASE help me if you know the answer!! :)
Gennadij [26K]
360/9= 40
180-40= 140
140/2= 70

X=70
4 0
3 years ago
Pamela wants to learn more about the career preferences of students in her school. She interviews a number of students from the
mixas84 [53]
Hi, the answer should be 3 :)
6 0
3 years ago
Read 2 more answers
(2.2.5) In horse racing, one can make a trifecta bet by specifying which horse will come in first, which will come in second, an
DaniilM [7]

Answer:

56 ways.

Step-by-step explanation:

This question is solved by using combinations and permutations chapters in the math book.

To put it simply, we need to find the number of 3 horse combinations we can make from 8 horses. This requires the combinations formula:

C(n,r)=\frac{n!}{r!(n-r)!}

here n is the total number of objects to choose from, and r is the number of objects we require in the combination or group.

Since there are 8 horses, n= 8

Since we need to choose only 3 of them, and order does not matter, r= 3

Solving the equation above using these inputs gives us 56 unique ways we can choose the three winners.

7 0
3 years ago
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