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3 years ago

Cassandra wants to solve the Quetion 30 equals 2/5 Pete. What operation should she perform to isolate the variable

1 answer:

5 0

It sounds like you are setting up the equation below.
(2/5)P = 30

To solve this equation for P, you would multiply both sides of the equation by 5/2.

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HELP ME!!!<br> What is 1x0=???<br> (I honestly dunno ._.)

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Answer:

good one

Step-by-step explanation:

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3 years ago

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What's the slope of (-5, 10) and (-2, -2)?

3241004551 [841]

Answer:

slope: -4

equation: y = -4x – 10

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3 years ago

last month a parking lot had 22 spaces in each of its rows recently the lot expanded and 4 spaces were added to each row if the

Vika [28.1K]

368 spaces now, why?
There are 22 spaces per row, and we know there are 8 rows, so thats 176 spaces last month,
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4 years ago

use the picture to write each ratio as a simplified fraction (how are you going to find the length of the third side?) show your

Butoxors [25]

Answer:

<h3>See below</h3>

Step-by-step explanation:

to figure out the ratios we must figure out the length of <u>hypotenuse</u> first to do so we can consider <u>Pythagoras</u><u> theorem</u> given by

$\displaystyle {a}^{2} + {b}^{2} = {c}^{2}$

$\displaystyle \implies c = \sqrt{ {a}^{2} + {b}^{2} }$

substitute:

$\displaystyle c = \sqrt{ {12}^{2} + {9}^{2} }$

simplify squares:

$\displaystyle c = \sqrt{ 225 }$

simplify square root:

$\displaystyle c = 15$

now recall that,

$\displaystyle \sin( \theta) = \frac{opp}{hypo}$
$\displaystyle\cos( \theta) = \frac{adj}{hypo}$
$\displaystyle \tan( \theta) = \frac{opp}{adj}$

the ratios with respect to angle w given by

$\displaystyle \sin( W) = \frac{12}{15} = \frac{4}{5}$
$\displaystyle \cos(W) = \frac{9}{15} = \frac{3}{5}$
$\displaystyle \tan( W) = \frac{12}{9} = \frac{4}{3}$

the following ratio with respect to angle X

$\displaystyle \sin(X) = \frac{9}{15} = \frac{3}{5}$
$\displaystyle \cos(X) = \frac{12}{15} = \frac{4}{5}$
$\displaystyle \tan( X) = \frac{9}{12} = \frac{3}{4}$

7 0

3 years ago

Can someone help me and explain this Algebra 2?

Tju [1.3M]

Nth term of gp = a(1 - r^n)/(1 - r), where n∞ = 10, n = ∞, a = 2, r < 1
10 = 2(1 - r^∞)/(1 - r)
10 = 2/(1 - r)
1 - r = 2/10 = 1/5
r = 1 - 1/5 = 4/5
An infinite deometric series with a beginning value of 2 that converges to 10 has common ratio of 4/5.

The first four terms are: 2, 1.6, 1.28, 1.024

5 0

3 years ago