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3 years ago

Can someone help me and explain this Algebra 2?

1 answer:

5 0

Nth term of gp = a(1 - r^n)/(1 - r), where n∞ = 10, n = ∞, a = 2, r < 1
10 = 2(1 - r^∞)/(1 - r)
10 = 2/(1 - r)
1 - r = 2/10 = 1/5
r = 1 - 1/5 = 4/5
An infinite deometric series with a beginning value of 2 that converges to 10 has common ratio of 4/5.

The first four terms are: 2, 1.6, 1.28, 1.024

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What is the slope of the the line shown below?

ollegr [7]

Answer:

The answer is A. -2/7

Step-by-step explanation:

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3 years ago

How you save 6x-2=5x+29

dolphi86 [110]

6x-2=5x+29
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3 years ago

A tank has the shape of an inverted circular cone (point at the bottom) with height 10 feet and radius 4 feet. The tank is full

german

Answer:

Step-by-step explanation:

Given that tank has the shape of inverted circular cone

Height = 10 feet and radius = 4 feet

After water pumped out height = 5 ft

Hence volume of water pumped out = $\frac{1}{3} \pi R^2 h-\frac{1}{3} \pi r^2 h'$

Here we have r/h is constant always

Hence $\frac{r}{h'} =\frac{R}{h} \\r=Rh'/h = 4(5)/10 = 2$

Substitute to get volume of water pumped out = $\frac{1}{3} \pi (10*16-4*5)=\frac{140\pi}{3}$

Mass of water = density x volume = $62.4(\frac{140\pi}{3})\\= 2912\pi lbs$

Work done = force x displacement

= mass x accen x displacement

Here acceleration = gravity = 32.2 ft/sec^2

Displaement = height reduced = 5 ft

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3 years ago

Help show work <br> assig 8

ELEN [110]

Answer:

Step-by-step explanation:

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3 years ago

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$

$P(20 \leq x \leq 30) =99.84\%$

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4 years ago