Answer:
7 and 1
Step-by-step explanation:
Let the numbers be a and b.
<u>A positive number is 7 times another number:</u>
<u>If 3 is added to both the numbers then one of the new number becomes 5 by 2 times the other new number:</u>
<u>To solve this we substitute </u><u>a</u><u> with </u><u>7b</u><u> in the second equation:</u>
- 7b + 3 = 5/2 × (b +3) ⇒ multiplying both sides by 2
- 14b + 6 = 5b + 15 ⇒ collecting like terms
- 14b - 5b = 15 - 6
- 9b = 9
- b = 1 ⇒ solved for b
<u>Then, finding a:</u>
- a= 7b
- a=7*1
- a= 7 ⇒ solved for a
<u>So the numbers are</u> 7 and 1
Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Since we're doing compound interest for four years it will be simpler than daily.
In case you didn't know the formula, here it is: A = P (1 +r/n)^(nt)
now lets substitute.
A = 500 (1 + 0.03)^4
A = 500 (1.03)^4
A = 500 (1.12550881)
A = 562.754405
Since that decimal is too big for cash, let's round it. Notice that the number after 5 is lower than 5. Thus the first two numbers stay the same and the final answer will be..
A = 562.75
Hope this helps :3
Answer:
Step-by-step explanation:
U need to think
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