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murzikaleks [220]
3 years ago
6

For an apartment complex, the association collects $158,000 from all of its 211 residents. What is the average rent per capita f

or this apartment complex?
Mathematics
1 answer:
matrenka [14]3 years ago
5 0
Each person has a rent of about $749
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two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rat
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container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

<u>Step-by-step explanation:</u>

Here we have , two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rate of 1/4 cup per 3/4 minute. water enters container b at a rate of 3/4 cup per 1/2 minute and leaks out at a rate of 1/2 cup per 3/4 minute. We need to find which container needs to be filled faster in order for both containers to gain the same amount of water per minute . Let's find out:

Rate of Filling container A:

⇒ \frac{\frac{2}{3} }{\frac{1}{2} }

⇒ \frac{2}{3} (2) = \frac{4}{3}

Rate of leaking Container A:

⇒ \frac{\frac{1}{4} }{\frac{3}{4} }

⇒ \frac{1}{4} (\frac{4}{3}) = \frac{1}{3}

Amount of water in Container A in one minute :

⇒ \frac{4}{3}  - \frac{1}{3} = 1

No , following same for Container B

Rate of Filling container B:

⇒ \frac{\frac{3}{4} }{\frac{1}{2} }

⇒ \frac{3}{4} (\frac{2}{1}) = \frac{3}{2}

Rate of leaking Container B:

⇒ \frac{\frac{1}{2} }{\frac{3}{4} }

⇒ \frac{1}{2} (\frac{4}{3}) = \frac{2}{3}

Amount of water in Container B in one minute :

⇒ \frac{3}{2}  - \frac{2}{3} = \frac{5}{6}

Since , Rate of water per minute in container A is 1 and , Rate of water per minute in container B is 5/6 , container A fills faster by container B by

⇒ 1-\frac{5}{6} = \frac{1}{6}

Therefore , container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

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