Answer:
Exact circumference is 
Approximate circumference is 
Step-by-step explanation:
We are given;
- The diameter of a circle as

We are required to determine the exact and approximate circumference of the circle.
- We know that the circumference of the circle is given by;
- Circumference = πD, where D is the diameter
Taking π as 3.14


The exact circumference of the circle is 

Thus, the approximate circumference of the circle is 
Step-by-step explanation:
eggs used : 50-12= 38 eggs

Answer:
Two figures that have the same shape are said to be similar. When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles below are similar, compare their corresponding sides.
Area shaded = Area big circle- Area of small circle;
200 pi= pi•(2x)^2 -pi•6^2;
200pi= pi•4x^2 -pi•36;
200pi=pi•4(x^2 -9) divide both sides by 4pi;
50=x^2 -9; So x=sqrt(59)~7.68cm