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Inessa05 [86]
3 years ago
10

6 times 7 -3 squared by 2 times 9 +4 squared by 3

Mathematics
2 answers:
koban [17]3 years ago
8 0
6 x 7 = 42
42 - 3^2 = 33
33 times 9 = 297
297 + 4^3 = 361

361 is your answer, I believe.
timama [110]3 years ago
7 0
I believe that the answer is 25
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Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

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Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

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\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

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\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

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also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

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