Let the cost of 1 ribeye steak dinner = x
The cost of 1 salmon dinner = y
Then,
11x + 18y = 592.29 (1)
16x + 6y = 580.56 (2)
Multiplying the second equation by 3, we get,
48x + 18y = 1741.68 (3)
(3) - (1) gives
37x = 1149.39
x = 31.06
Substituting the value for x in (1), we get,
11(31.06) + 18y = 592.29
341.66 + 18y = 592.29
18y = 250.63
y = 13.92
Hence, the cost of ribeye steak dinner = 31.06 and the cost of grilled salmon dinner = 13.92.
Answer:
I cant answer it because you cant copy it it doesnt allow me
Answer:
5/35 both or 14.285%
Step-by-step explanation:
15/35 honor students
10/35 athletes
5/35 both or 14.285%
I could be wrong.
The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
