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ElenaW [278]
2 years ago
14

un objeto cae accidentalmente de un vehículo que lleva una rapidez de 50 kilómetros por hora y recorre 20 m antes de detenerse​

Mathematics
1 answer:
Svet_ta [14]2 years ago
5 0

Un objeto cae accidentalmente de un vehículo con una velocidad de

50 km / hy recorra 20 m antes de detenerse.

Calcular:

a) La aceleración:

b) El tiempo que tarda en detenerse:

Responder:

1.439 s

-9,645 m / s²

Explicación paso a paso:

Dado que:

Velocidad en m / s = (50 * 1000) / 3600 = 13.899 m / s

Distancia (d) = 20

Tiempo = distancia / velocidad

Tiempo = 20 / 13.889

Tiempo = 1.439 s

Aceleración (a):

Cambio de velocidad / tiempo empleado

= (0 - 13,889) / 1,439

- 13.889 / 1.439

= -9,645 m / s²

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Read 2 more answers
The equation 6y = 30 - 8x has solutions of (b, 1) and (a, b).<br> What are the values of a and b?
victus00 [196]

The values of a and b are a = \frac{3}{2} and b = 3, respectively.

In this question we need to solve the linear equation for each point, first for (x,y) = (b, 1) and later for (x,y) = (a, b).

If we know that (x,y) = (b, 1), then the value of b is:

6 = 30-8\cdot b

8\cdot b = 24

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If we know that (x,y) = (a, b) and b = 3, then the value of a is:

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The values of a and b are a = \frac{3}{2} and b = 3, respectively.

To learn more on linear functions, we kindly invite to check this question: brainly.com/question/5101300

6 0
2 years ago
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